This **calculator** can determine the resonant frequency of an LC **circuit** which basically is a **circuit** consisting of an inductor and a capacitor and is also known as a tuned **circuit**. ... Then input the numbers, click calculate and your answer is 2.0264e+3 microhenrys or 2.0264 millihenrys or .0020264 henrys. In other words forming an **LR Series Circuit**. A **LR Series Circuit** consists basically of an inductor of inductance, L connected in series with a resistor of resistance, R. The resistance “R” is the DC resistive value of the wire turns or loops that goes into making up the inductors coil. Consider the **LR series circuit** below.. With this RC **calculator**, you can get an intuitive understanding of what happens with a charging and discharging RC **circuit** **in** the time domain. With only the values of the resistor and capacitor, we can find the time constant of the RC **circuit**, also known as tau, which is the amount of time required to charge or discharge a capacitor in series. . The waveform and power curve of the **RL** series **circuit** is shown below: The various points on the power curve are obtained by the product of voltage and **current**. If you analyze the curve carefully, it is seen that the power is negative between angle 0 and ϕ and between 180 degrees and (180 + ϕ) and during the rest of the cycle the power is. independent of the **current** I1 in the coil. 11.2 Self-Inductance Consider again a coil consisting of N turns and carrying **current** I **in** the counterclockwise direction, as shown in Figure 11.2.1. If the **current** is steady, then the magnetic flux through the loop will remain constant. However, suppose the **current** I changes with time, 11-5. This video will be the first in a long playlist covering every different RLC **circuit** that exists. We'll start first with an **RL** Single Phase Series **Circuit** Ca.... Numerical Example. The applied voltage in a parallel RLC **circuit** is given by. ν = 100 s i **n** ( 314 t + π 4) V. If the values of **R**, **L** and C be given as 30 Ω, 1.3 mH and 30 μF, Find the total **current** supplied by the source. Also find the resonant frequency in Hz and corresponding quality factor. Dynamic electric **circuits** involving linear time-invariant resistors, capacitors, and inductors are described by linear constant coefficient differential equations (LCCDE). Mathematical solution of such LCCDE requires some physical (electrical **circuit** theoretic) insight too. This is especially true for solving **circuits** under impulse functions (such as finding impulse responses). This simulation shows the changing **current** and voltage in an **RL circuit**. Click the play button in the bottom left corner to start the simulation. Click on the switches to change how **current** flows through the **circuit**. Use the sliders to adjust the EMF, resistance, and inductance of the **circuit**. Use the drop-down menu to the left of the graph to. Inductance of the inductor ( L) H. Capacitance of the capacitor ( C) F. Archimedes constant ( π) Phase Constant in a RLC **Circuit** **Calculator** Results (detailed calculations and formula below) The Phase constant is rad [radian] Phase constant calculation. φ = arctan 2 × π × f d × L - 1. /. 2 × π × f d × C. Knee Point Voltage Formula: CT Knee Point Voltage can be calculated using the formula; Vkp = K * If/CTR * (RCT + **RL** + RR) Where, K = Constant, conventionally taken as 2.0. Vkp = The minimum Knee Point Voltage. If = Maximum Fault **Current** at the location, in Amperes. CTR = CT Ratio. RCT = CT Secondary Winding Resistance, in Ohms. The characteristic frequenct has two applications. They are RC **Circuit** is used as filter and capacitor charge time. The formula to get the characteristic frequency of the RC **Circuit** is follows: f = 1/ (2π * R * C) Where, R is the resistance of the resistor. C is the capacitance of the capacitor. f is the characteristic frequency. Instantaneous **Current** Calculations of an Energizing **RL** **Circuit** (**Calculator** TI-30XIIS) By Terry Bartelt Students view the keystrokes of a TI-30XIIS **calculator** that are required to solve for the instantaneous **current** of an energizing **RL** **circuit**. Related Questions Series **RL** **Circuit** Practice Problems By James Bourassa, John Rosz. EXAMPLE. 14. A **current** of 2 A flows through a resistor in series with a coil while 200 V is applied across the combination at 50 Hz. If the voltage across the resistor is 100 V while that across the coil is 150 V. Calculate (a) the impedance, resistance and reactance of the coil, (b) the power absorbed by the coil , (c) the total power. Solution:. The constant L/R is called the time constant.The time constant provides a measure of how long an inductor **current** takes to go to 0 or change from one state to another. To analyze the **RL** parallel **circuit** further, you must calculate the **circuit's** zero-state response, and then add that result to the zero-input response to find the total response for the **circuit**. When working with the analytical solution for an RLC **circuit**, the behavior of an RC or **RL** **circuit** can be found by taking L = 0 or C = 0 respectively in the solution for the relevant RLC **circuit**. Note that an inductor in parallel with a resistor (**RL** **circuit**) will essentially form a short **circuit** when used with a DC source. A **circuit** with resistance and self-inductance is known as an **RL** **circuit**. (a) shows an **RL** **circuit** consisting of a resistor, an inductor, a constant source of emf, and switches and When is closed, the **circuit** is equivalent to a single-loop **circuit** consisting of a resistor and an inductor connected across a source of emf ((b)).. RLC series A.C. **circuits**. The e.m.f. that is supplied to the **circuit** is distributed between the resistor, the inductor, and the capacitor. Since the elements are in series the common **current** is taken to have the reference phase. A 240V, 250/π Hz supply is connected in series with 60R, 180mH and 50μF. **Current** (when rising) in the circuit at any instant Formula and** Calculation** i 1 (t) = ε R × 1 - e - R × t L** Current** (when dropping) in the circuit at any instant Formula and** Calculation** i (t) =** ε R** ×** e - R** × t L Magnetism Physics Tutorials associated with the** Current** In A** Rl Circuit Calculator**. . This series **RL circuit** impedance **calculator** determines the impedance and the phase difference angle of an inductor and a resistor connected in series for a given frequency of a sinusoidal signal. The angular frequency is also determined. Example: **Calculate** the impedance of a 500 mH inductor and a 0.2 Ω resistor at a frequency of 25 kHz. . A Resistor **Circuit** An AC generator with a maximum voltage of 24.0 V and a frequency of Find (a) the rms voltage andthe rms voltage and (b) the rms **current** **in** the **circuit** Determinethe rms **current** **in** the **circuit**. Determine (c) the average and (d) maximum power dissipated in the resistor. 18. As we will see, the behavior of the **current** and voltage in this **RL** **circuit** is in many ways opposite to the behavior of **current** and voltage in the RC **circuit**, **in** the sense that the **current** **in** the **RL** **circuit** behaves like the voltage in the RC **circuit**, and vice versa. EXPLORATION AC.2 - **RL** **Circuits** **In** the **RL** **circuit** **in** Figure AC.3, the.

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. EE 43/100 RC **Circuits** 5 V C (t) t V IN (t) t t V X (t) ∝ VIN(t) - VC(t) V X (t) V0 - V0 V0 Figure 6: Voltage waveforms in a series RC **circuit** (d) From voltage VX across RX, you could use Ohm's Law to obtain the **current** IX, but both IX and VX will have the same time constant. You should trigger on A1 edge and set Main Time Ref to Left, and always use the knobs to zoom in upon your cursor. MFMcGraw-PHY 2426 Chap31-AC **Circuits**-Revised: 6/24/2012 2 Alternating **Current** **Circuits** • Alternating **Current** - Generator • Wave Nomenclature & RMS • AC **Circuits**: Resistor; Inductor; Capacitor ... • Impedance and Power • RC and **RL** **Circuits** - Low & High Frequency • RLC **Circuit** - Solution via Complex Numbers • RLC **Circuit** - Example. Phase Shift for an **RL** **Circuit**. 34 Filter **circuits** that use inductors (such as those shown in Figure 6.51) produce a phase shift in the output signal, just as filter **circuits** containing capacitors do.You can see the shifts for the **circuits** shown in Figure 6.51 by comparing the input and output waveforms shown below the **circuit** diagrams. The point p shown on graph indicates that **current** **in** **circuit** rises to 0.632 time's maximum value of **current** **in** steady state. "the time required for the **current** to rise to the 0.632 of its final value is known as time constant of given **RL** **circuit**. The time constant is denoted by z". Thus for series **RL** **circuit**, time constant is. (a) For the **circuit** **in** Fig. 4.138, obtain the Thevenin equivalent at terminals a-b. (b) Calculate the **current** **in** = 8Ω. (c) Find for maximum power deliverable to . (d) Determine that maximum power. (a) For the **circuit** **in** Fig. 4.138, obtain the Thevenin equivalent at terminals a-b. (b) Calculate the **current** **in** = 8Ω. (c) Find for maximum power deliverable to . (d) Determine that maximum power. (a) An **RL** **circuit** with a switch to turn **current** on and off. When in position 1, the battery, resistor, and inductor are in series and a **current** is established. In position 2, the battery is removed and the **current** eventually stops because of energy loss in the resistor.. i(∞) = **Current** through the inductor at t → ∞. i(0) = **Current** through the inductor at t = 0. R eq = Thevenin's equivalent resistance seen across the L for t > 0. Calculation: Given that L = 1H and R = 10 Ω and the DC supply of 100 V applied at the time t = 0. Consider the **circuit** at t → ∞. I(∞) = 100/10. i(∞) = 10 A. Consider. I miss here **current**, voltage calculation based on input voltage. That would bring this **calculator** o outstanding level. ... Calculation of impedances of RLC **circuit** [7] 2018/08/14 23:03 30 years old level / A teacher / A researcher / Very / ... To improve this 'Impedance of RC and **RL** **in** parallel **Calculator'**, please fill in questionnaire. Age. **In** the given **circuit**- the value of **current** IL will be _____ mA. (When **RL** = 1kΩ) Login. Remember. Register; Test; ... following data is given **RL** = 1KΩ Vin = 10mV, ΔIB = 15 µA. asked Apr 11, 2019 in ... 1 answer. For the **circuit** diagram shown below, calculate the load **current** across 1kΩ resistor. i = ? asked Jul 1 in Physics by Tanishkajain. The phasor diagram for a parallel **RL circuit** shows that the total **current** wave lags behind the total voltage wave. The lag is less than 90° and more than 0°. At 90° the resistor is removed from the **circuit** (the **circuit** is purely inductive) and at 0° the inductor is removed from the **circuit** (the **circuit** is purely resistive). "/>. An **RL** **circuit** has an emf of 5 V, a resistance of 50 Ω, an inductance of 1 H, and no initial **current**. Find the **current** **in** the **circuit** at any time t. Distinguish between the transient and steady-state **current**. Answer. Method 1 - Solving the DE. The formula is: `Ri+L(di)/(dt)=V`. parasites pronunciation; easy coding esp32; old man called me beautiful; spain x reader lemon; a shadow in the ember special edition; how to turn off tracking on. Ohm's law formula. The resistor's **current** I in amps (A) is equal to the resistor's voltage V in volts (V) divided by the resistance R in ohms (Ω): V is the voltage drop of the resistor, measured in Volts (V). In some cases Ohm's law uses the letter E to represent voltage. E denotes electromotive force. I is the electrical **current** flowing. **RL Time Calculator** The drawing at the left illustrates an inductor with a series resistance and switch combination connected to a battery. The time required for the **current** to rise to 63.2% of the maximum value after the switch is closed is the ratio of inductance to resistance (L/R). ... The **current** will increase from 0 to 632 milliamps in 1. These calculations waste a lot of time. This **circuit** design **calculator** software developed in MATLAB, JavaScript, etc help you solve, analyse and determine the **circuit** design with capacitors, inductors, resistors, diodes, transistors and other components. The software can provide answers to many complex analogue and digital **circuit** design problems. Part 1.2: RC&**RL** **circuits** . The fundamental passive linear **circuit** elements are the resistor (R), capacitor (C) and inductor (L) or coil. These **circuit** > elements can be combined to form an electrical **circuit** in four distinct ways: the RC **circuit**, the **RL** **circuit**, the LC **circuit** and the RLC **circuit** with the abbreviations indicating which components.. Insert these values into Ohm's Law. Rearrange V = IR to solve for resistance: R = V / I (resistance = voltage / **current**). Plug the values you found into this formula to solve for total resistance. For example, a series **circuit** is powered by a 12 volt battery, and the **current** is measured at 8 amps. The parallel resistor **calculator** has two different modes. The first mode allows you to **calculate** the total resistance equivalent to a group of individual resistors in parallel. In contrast, the second mode allows you to set the desired total resistance of the bunch and **calculate** the one missing resistor value, given the rest.. To keep it simple, we only show you a few rows to input. Students view the keystrokes of a TI-30XIIS **calculator** that are required to solve for the instantaneous **current** of an energizing **RL** **circuit**. Instantaneous **Current** Calculations of an Energizing **RL** **Circuit** (**Calculator** TI-30XIIS) - Wisc-Online OER. To **calculate** Voltage across Output in Amplifier, you need Open **circuit** voltage gain (A vo), Input voltage (V i), Load Resistance (**Rl**) & Output resistance (Ro). With our tool, you need to enter the respective value for Open **circuit** voltage gain, Input voltage, Load Resistance & Output resistance and hit the **calculate** button.. The point p shown on graph indicates that **current** **in** **circuit** rises to 0.632 time's maximum value of **current** **in** steady state. "the time required for the **current** to rise to the 0.632 of its final value is known as time constant of given **RL** **circuit**. The time constant is denoted by z". Thus for series **RL** **circuit**, time constant is. First, calculate total resistance: 4 + 2 + 6 = 12 Ω. Next, calculate the **current**: 24 V/12 Ω = 2 A. Now, use the **current** to calculate the voltage drop across each resistor. Using V = IR for each, the values of R 1, R 2 and R 3 are 8 V, 4 V and 12 V. **Calculating** impedences of motor **circuits** ... To improve this 'Impedance of RC and **RL** in parallel **Calculator**', please fill in questionnaire. Age ... I miss here **current**, voltage **calculation** based on input voltage. That would bring this **calculator** o outstanding level. [2] 2021/10/01 02:34 20 years old level / High-school/ University/ Grad student. The load requires a **current** which varies between 200 and 350 mA. (milliamps). A 9.1 volts zener diode is chosen (very close to the 9 volts value) Rs resistor calculation: Rs = (15 - 9.1) / (1.1 x 0.35) = 15 ohms. Zener diode power calculation: PD = [ (15 - 9.1) / 15] x 9.1 = 3.58 watts. As there is no 3.58 watts zener diode, we choose a 5. Series **RL Circuit** Analysis Since the value of frequency and inductor are known, so firstly **calculate** the value of inductive reactance XL: XL = 2πfL ohms. From the value of XL and R, **calculate** the total impedance of the **circuit** which is given by. **Calculate** the total phase angle for the **circuit** θ. Enter up to 10 resistors. This **Current Divider Calculator** can **calculate** the **current** going through any branch in a parallel **circuit**, using the formula shown above. When a **circuit** is in parallel, the total **current** coming from the power source divides up into each of the branches of the **circuit**, based on the resistance values of each of the branches.. Steps to calculate Thevenin's equivalent **circuit**. Remove the load resistance. After short circuiting all the voltage sources and open circuiting all **current** sources, find the equivalent resistance (R th) of the **circuit**, seeing from the load end.; Now, find V th by usual **circuit** analysis.; Draw Thevenin's equivalent **circuit** with V th, R th and load. From this **circuit** we can calculate I L. **Current** measurements of a parallel **RL circuit** indicate a **current** flow of 2 amperes through the resistive branch and 4 amperes through the inductive branch. Determine: The value of the total **current** flow. The phase angle between the voltage and total **current**. For the parallel **RL circuit** shown in Figure 8, determine: Apparent power. True power. Question: Calculate the **current** through R in the **circuit** below. You don't need to build this **circuit**. Be sure to show your work below. (This problem is question from 19 in Chapter 8 of the textbook.) 10 k.12 10 k 12 VOUT w 10 k.12 w 3.2 V = 5.6 k 12 5.6 k12 w **RL** 15 k12 = Extra: If you have time, build the **circuit** and measure Vout- VOUT V. Formulae for **Series R L Circuit Impedance** Used in **Calculator** and their Units. Let f be the frequency, in Hertz, of the source voltage supplying the **circuit**. and define the following parameters used in the **calculations**. ω = 2 π f , angular frequency in rad/s. X L = ω L , the inductive reactance in ohms ( Ω). Apply the rule of impedances of a series ciruits to find the equivalent impedance Z as follows. Z = R + Z C + Z L Let. X L = ω L and X C = 1 ω C. and rewrite Z as. Z = R + 1 j ω C + j ω L. Z = R + j ( − X C + X L) We now use the exponential form of complex number to write. Z = r e j θ. the modulus of Z as. The constant L/R is called the time constant.The time constant provides a measure of how long an inductor **current** takes to go to 0 or change from one state to another. To analyze the **RL** parallel **circuit** further, you must **calculate** the **circuit**’s zero-state response, and then add that result to the zero-input response to find the total response for the **circuit**. Jul 25, 2022 · To design **parallel** **RL** **circuit** and find out the **current** flowing thorugh each component. Apparatus: Resistor, Capacitor, AC power source, ammeter, voltmeter, connection wire etc.. Theory: With an ac signal applied to it, the **parallel** **RL** **circuit** shown below offers significant impedance to the flow of **current**.. Insert these values into Ohm's Law. Rearrange V = IR to solve for resistance: R = V / I (resistance = voltage / **current**). Plug the values you found into this formula to solve for total resistance. For example, a series **circuit** is powered by a 12 volt battery, and the **current** is measured at 8 amps. Part 1.2: RC&**RL circuits** . The fundamental passive linear **circuit** elements are the resistor (R), capacitor (C) and inductor (L) or coil. These **circuit** elements can be combined to form an electrical **circuit** in four distinct ways: the RC **circuit** , the **RL circuit** , the LC **circuit** and the RLC <b>**circuit**</b> with the abbreviations indicating which components. Study **RL Series circuits flashcards** from Chamour Labbe's class online, ... What is the formula for applied voltage after total impedance (Zt) is **calculated**? EA = Sq Root of: ER 2 + EL 2. 11 ... **In RL** series **circuits**, voltage leads **current** by _____ degrees.. **In** the given **circuit**- the value of **current** IL will be _____ mA. (When **RL** = 1kΩ) Login. Remember. Register; Test; ... following data is given **RL** = 1KΩ Vin = 10mV, ΔIB = 15 µA. asked Apr 11, 2019 in ... 1 answer. For the **circuit** diagram shown below, calculate the load **current** across 1kΩ resistor. i = ? asked Jul 1 in Physics by Tanishkajain. parasites pronunciation; easy coding esp32; old man called me beautiful; spain x reader lemon; a shadow in the ember special edition; how to turn off tracking on. **RL** Low **Pass Filter - Frequency and Bode Plot Calculator**. This tool calculates the crossover frequency for a **RL** low pass filter. In addition, it graphs the bode plot for magnitude in decibels and the phase in radians. The graph is unable to plot below 1Hz at the moment. The output frequency is rounded to the second decimal place. Please notify .... For drawing the phasor diagram of series **RL** **circuit**; follow the following steps: Step- I. In case of series **RL** **circuit**, resistor and inductor are connected in series, so **current** flowing in both the elements are same i.e I R = I L = I. So, take **current** phasor as reference and draw it on horizontal axis as shown in diagram. Step- II. IEC 60909: Short-**Circuit** **Current** Calculation in Three-Phase A.C. Systems. European Standard EN 60909 German National Standard DIN VDE 0102 further National Standards. Engineering Recommendation G74 (UK) ... **RL** R' XL X' **RL** 0.3 / km 10 km XL 0.4 / km 10 km. **RL** 3.0000 XI 4.0000. So then, for two ohm resistor to calculate the **current** here, I would substitute R as two, V is 50, calculate the **current**. Then for 40 Ohm resistor, I would put V is 50, that's already given, R is 40. Calculate the **current**, same thing over here. And we are done. We now know **current** through each resistor. Power Factor Correction Example No1. An **RL** series **circuit** consists of a resistance of 15Ω and an inductor which has an inductive reactance of 26Ω. If a **current** of 5 amperes flows around the **circuit**, **calculate**: 1) the supply voltage. 2) the phase angle between the supply voltage and **circuit current**. 3) Draw the resulting phasor diagram. **RL Circuits** R I a b L I •At t=0, the switch is closed and the **current** I starts to flow. Initially, an inductor acts to oppose changes in **current** through it. A long time later, it acts like an ordinary connecting wire. 3/21/2017 4 **RL Circuits** R I a b L I • Find. Related: resistor **calculator** Ohm's Law. Ohm's Law states that the **current** through a conductor between two points is directly proportional to the voltage. This is true for many materials, over a wide range of voltages and currents, and the resistance and conductance of electronic components made from these materials remain constant. Students view the keystrokes of a TI-30XIIS **calculator** that are required to solve for the instantaneous **current** of an energizing **RL** **circuit**. Instantaneous **Current** Calculations of an Energizing **RL** **Circuit** (**Calculator** TI-30XIIS) - Wisc-Online OER. RC and **RL** **Circuits** Rules to remember •ELI the ICE man: Voltage (E) leads **Current** (I) in an Inductive (L) **circuit** , whereas **Current** (I) leads Voltage (E) in a Capacitive (C) **circuit** -This is only true for SERIES **circuits**. When it goes into a parallel configuration, the opposite occurs •**Current** leads Voltage in a Parallel Inductive **circuit**. Series **RL Circuit** Analysis Since the value of frequency and inductor are known, so firstly **calculate** the value of inductive reactance XL: XL = 2πfL ohms. From the value of XL and R, **calculate** the total impedance of the **circuit** which is given by. **Calculate** the total phase angle for the **circuit** θ. parasites pronunciation; easy coding esp32; old man called me beautiful; spain x reader lemon; a shadow **in **the ember special edition; how to turn off tracking on iphone without the person knowing. UL 508A Calculation Method. Step 1: Determine the short **circuit** **current** rating all individual power **circuit** components by using one of the following methods: Use the short **circuit** **current** rating marked on the component or on the specifications provided with the component. For unmarked components, use the assumed short **circuit** **current** rating. Answer: 0.0000000000s. The Time Constant **Calculator** calculates the time constant for either an RC (resistor-capacitor) **circuit** or an **RL** (resistor-inductor) **circuit**. The time constant represents the amount of time it takes for a capacitor (for RC **circuits**) or an inductor (for **RL circuits**) to charge or discharge 63%. Answer to Calculate the resistance in an **RL** **circuit** **in** which L = 2.50 H and the **current** increases to 90.0% of its final value in 3.00 s. | SolutionInn. For the following **circuit**, calculate (i) **circuit** admittance, (ii) total impedance, (iii) total **current**, (iv) **current** through R & L, (v) power factor, (vi) ac. This **calculator** is based on simple Ohm’s Law. As we have already shared Ohm’s Law (P,I,V,R) **Calculator** In which you can also **calculate** three phase **current**. But we have designed this one especially for DC **Circuits** (as well as work for Single Phase AC **circuits** without Power Factor (We will share another **calculator** for Power Factor .... Characteristics. ①Current: I=I1=I2 (the **currents** **in** all parts of the series **circuit** are equal) ②Voltage: U=U1+U2 (the total voltage in the series **circuit** is equal to the sum of the voltages of each part of the **circuit**) ③Resistance: R=R1+R2 (the total resistance in the series **circuit** is equal to the sum of the series resistances); if n. 3 **RL** **Circuits** A series **RL** **circuit** with a voltage source V(t) connected across it is shown in Fig. 1. Figure 1: The loopy arrow indicates the positive direction of the **current**. The + and signs indicate the positive values of the potential di erences across the components. The voltage across the resistor and inductor are designated by V R and V. because the open **circuit** voltage and short **circuit** **current** will both be 0, so you can't take the ratio. See the example later. Example Let's verify the Thevenin resistance of the **circuit** we solved above. In the **circuit** below, we have deactivated the two voltage sources (they are replaced by short **circuits**), and the **current** source. 3 **RL Circuits** A series **RL circuit** with a voltage source V(t) connected across it is shown in Fig. 1. Figure 1: The loopy arrow indicates the positive direction of the **current**. The + and signs indicate the positive values of the potential di erences across the components. The voltage across the resistor and inductor are designated by V R and V. To determine the value of c in Eq. 12.5, we use the initial conditions. In the Transient Response of **RL** **Circuit** shown in Fig. 12.1, the switch S is closed at t=0. At t=0 -, i.e. just before closing the switch S, the **current** **in** the inductor is zero. Since the inductor does not allow sudden changes in **currents**, at t=0 + just after the switch is.

rlcircuits.... « Reply #4 on: February 09, 2014, 07:28:43 am » calculate the time constant, times it by 5, then round up to the nearest decade, then take 5+ samples per time constantcircuit calculator, you cancalculatethe resonant frequency and the Q-factor of any RLCcircuitby providing capacitance, inductance and resistance values.. RLCcircuit. A RLCcircuitas the name implies consist of a Resistor, Capacitor and Inductor connected in series or parallel. Thecircuitforms an Oscillatorcircuitwhich is very commonly used in Radio receivers andSeries R L Circuit ImpedanceUsed inCalculatorand their Units. Let f be the frequency, in Hertz, of the source voltage supplying thecircuit. and define the following parameters used in thecalculations. ω = 2 π f , angular frequency in rad/s. X L = ω L , the inductive reactance in ohms ( Ω)RL CircuitAnalysis Since the value of frequency and inductor are known, so firstlycalculatethe value of inductive reactance XL: XL = 2πfL ohms. From the value of XL and R,calculatethe total impedance of thecircuitwhich is given by.Calculatethe total phase angle for thecircuitθ.